584. Find Customer Referee [Leetcode SQL Query Solution in Mysql]

Table: Customer

Column NameType
id int
namevarchar
referee_idint

In SQL, id is the primary key column for this table. Each row of this table indicates the id of a customer, their name, and the id of the customer who referred them.

Find the names of the customer that are not referred by the customer with id = 2.

Return the result table in any order.

The result format is in the following example.

Example 1:

Input:

idnamereferee_id
1Willnull
2Janenull
3Alex2
4Billnull
5Zack1
6Mark2

Output:

name
Will
Jane
Bill
Zack

Solution :  

select name from customer where referee_id != 2 or referee_id is null;

Explanation – 

SELECT name: This part selects the name column from the table customer and retrieves the names of customers based on the given conditions.

WHERE referee_id !=2 OR referee_id IS NULL: The WHERE clause filters the results based on two conditions connected by the OR operator:

a. referee_id != 2: This condition excludes rows where the referee_id is not equal to 2. It filters out customers whose referee_id is not 2.

b. referee_id IS NULL: This condition excludes rows where the referee_id is NULL. It filters out customers who have no referee (referee_id is not specified).

As a result, the query retrieves the names of customers whose referee_id is not equal to 2 or is NULL (customers who either have no referee or have a referee with a value other than 2).

The names “Will,” “Jane,” “Bill,” and “Zack” are returned because they satisfy the specified conditions

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